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2x-x+x*3=3x+4x^2/5
We move all terms to the left:
2x-x+x*3-(3x+4x^2/5)=0
We add all the numbers together, and all the variables
-(3x+4x^2/5)+x+x*3=0
Wy multiply elements
-(3x+4x^2/5)+x+3x=0
We get rid of parentheses
-4x^2/5-3x+x+3x=0
We multiply all the terms by the denominator
-4x^2-3x*5+x*5+3x*5=0
Wy multiply elements
-4x^2-15x+5x+15x=0
We add all the numbers together, and all the variables
-4x^2+5x=0
a = -4; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·(-4)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*-4}=\frac{-10}{-8} =1+1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*-4}=\frac{0}{-8} =0 $
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